C : Program to display tabs , backspaces visible in an unambiguous way

In my earlier post, we have seen "C : Program to replace multiples spaces with a single space" , today lets modify the same code to display tabs, backspaces.

Below is the program which does this job.

 #include   
 int main()  
 {  
   char c;  
   printf("Enter a line to display tabs \n");  
   while((c=getchar()) != '\n')  
   {  
     if(c == '\t')  
     {  
         putchar('\\');  
         putchar('t');  
     }  
     putchar(c);  
   }  
   printf("\n");  
   return 0;  
 }  

In above program,

• We read input character by character
• Check if its tab (\t). If tab, we output (\\) followed by (t) character which displays \t.
• If its not tab, we simply output the character.

Output of this program,

 mrtechpathi@mrtechpathi:~/Study/C/K_and_R$ ./a.out   
 Enter a line to display tabs   
 This  program     displays     the tabs     entered  
 This \t     program\t     displays\t     the tabs\t     entered  

C : Program to count spaces and tabs

In earlier post "Character counting in C", we have written a program to count number of characters, lets extend this further and count blanks, tabs and newlines.

 int main()   
 {   
   double char_count;   
   char input_char;   
   int tabs_count=0,spaces_count=0;   
   char input_val;   
    
   printf("\n Input a line to count spaces and tabs \n");   
    
   /* Reading a character */   
   input_char = getchar();   
    
   /* In a for loop read characters till end of line is encountered */   
   for(char_count = 0; input_char != '\n'; ++char_count)   
   {   
     /* Check if input character is a space */     
     if(input_char == ' ')   
     {   
       /* if space, increment space variable count */          
       ++spaces_count;     
     }      
     /* else if input character is a tab */   
     else if(input_char == '\t')   
     {   
       /* if tab increment tab count */             
       ++tabs_count;      
     }   
     /* Read next character to check if its space or tab */   
     input_char = getchar();       
   }   
    
   /* Finally print number of spaces and tabs read */   
   printf("\n Your input contains %d spaces, %d tabs \n",spaces_count,tabs_count);   
    
   return 0;    
 }  
   

In above program,

• We read a character
• In a for loop till end of line is encountered, we check each character entered is a space (' ') or tab('\t').
• Increment spaces_count and tabs_count variables accordingly
• Finally when new line is encountered, we print the space count and tab count.

Output of this program :

 mrtechpathi@mrtechpathi:~/Study/C/K_and_R$ ./a.out   
   
  Input a line to count spaces and tabs   
 will be giving a tab now     just one tab behind  
   
  Your input contains 9 spaces, 1 tabs  

Character counting in C using for loop !!!

Yesterday we learnt about "Character Counting in C"  using while loop. Today in order to illustrate the same character counting in C, we will trying using for loop. We will also try to use float or double datatype to store the character count.

Lets get started ....

 #include <stdio.h>  
 int main()  
 {  
   double char_count;  
   printf("\n Input characters to count \n");  
   for(char_count = 0; getchar() != '\n'; ++char_count);  
   printf("\n You have typed %.0f character :) \n",char_count);  
   return 0;  
 }  

Above program,

• Declares char_count as doube instead of int to make sure that the count is not overflow while taking the input. double takes relatively more time to overflow than int.
• Requests user to input characters
• Reads character by character using getchar() till end of the line
• As you can see, there is no body for for loop here because whole operation of character counting is done in for loop itself. This is the beauty of for loop.
• for loop and while loop they check the condition first and enter their body to execute the code which provides the programmer more flexibility of programming.
• Once a line is entered, program exits by printing the character count.
• One important thing to note here while printing is "%.0f",  usually printf uses %f for printing float or double. Since char_count is decalared as double, we use "%.0f" to supress the decimal point  and fraction part which is zero.

Now output of this program is..

 mrtechpathi@mrtechpathi:~/Study/C/K_and_R$ ./a.out   
  Input characters to count   
 This is single line of input  
  You have typed 28 character :)   

It's very simple but very useful snippet while coding !!

Exiting c program right after reading one line or after carriage return while reading input from stdin

Yesterday, we learnt about "C program that copies its input to its output one character at a time" , if you observe the program mentioned in this post, you will observe that we are taking the input from stdin (standard input) and outputting to stdout (each line) till EOF (End of the file) is reached.

Ideally stdin EOF is like forever. So, we end up pressing Ctrl+C to exit the program. Now to modify this program to exit right after one line or after a carriage return, we need to do a simple modification.
Replace EOF with '\n'. Yes its as simple as that.

 #include <stdio.h>  
 int main()  
 {  
   int c;  
   printf("Program exits after new line or carriage return \n");  
   printf("Start your input \n");  
   c = getchar();  
   while(c != '\n')  
   {  
     putchar(c);  
     c = getchar();  
   }  
 }  

Only difference you observe is in the while condition, "while(c != EOF) is changed to while(c != '\n')".

Output will be as below.

 mrtechpathi@mrtechpathi:~/Study/C/K_and_R$ ./a.out   
 Enter Ctrl+C is to exit  
 Start your input   
 just one line input  
 just one line input  

Hope you understood this simple concept !!!

C program that copies its input to its output one character at a time

I have been blogging few interesting how-to articles which I learn in my daily professional life. Its been a while I haven't blogged any.So, thought of just adding atleast a program per day (very challenging isn't ?) along with how-to articles.

I will start with C-programming. As everyone know "Kernighan & Ritchie" (K&R) is the best book to learn C programming. I will using examples in this book.

If you want any C snippet meanwhile, just drop me a comment will try and get it done for you.  I cant promise, but will try my best to do code for you.

Frist lets start with "C program that copies its input to its output one character at a time"

 #include <stdio.h>  
 int main()  
 {  
   int c;  
   printf("Enter Ctrl+C is to exit\n");  
   printf("Start your input \n");  
   c = getchar();  
   while(c != EOF)  
   {  
     putchar(c);  
     c = getchar();  
   }  
 }  

Above program is exact copy of a program in K&R, I have just added two printf statements to it.

When you compile and run this program, it accepts whatever the character you input from the keyboard and print them once you press enter (new line / carriage return).

It does this task forever because we have used "While( c != EOF )" in our above code snippet.
This while statements will be true till you reach EOF of stdin (standard input) which is forever.

So, in order to exit from running your program, you need to press "Ctrl+C" on your keyboard together.

Now lets run and see, output will be as below

 mrtechpathi@mrtechpathi:~/Study/C/K_and_R$ ./a.out   
 Enter Ctrl+C is to exit  
 Start your input   
 we are  
 we are  
 trying to print  
 trying to print  
 character by character  
 character by character  
 ^C  

Hope you learnt something new :).